Greatest Common Divisor (GCD)
Let $P$ and $Q$ be two positive integers. The computation of the greatest common divisor (GCD) can be formulated as a QUBO problem.
Let $p$, $q$, and $r$ be positive integers satisfying the following constraints:
\[\begin{aligned} p\cdot r &= P \\ q\cdot r &=Q \end{aligned}\]Clearly, $r$ is a common divisor of $P$ and $Q$. Therefore, the maximum value of $r$ satisfying these constraints is the GCD of $P$ and $Q$. To find such an $r$, we use $−r$ as the objective function in the QUBO formulation.
QUBO++ program
Based on the idea above, the following QUBO++ program computes the GCD of two integers,
P = 858 and Q = 693:
#include "qbpp.hpp"
#include "qbpp_easy_solver.hpp"
int main() {
const int P = 858;
const int Q = 693;
auto p = 1 <= qbpp::var_int("p") <= 1000;
auto q = 1 <= qbpp::var_int("q") <= 1000;
auto r = 1 <= qbpp::var_int("r") <= 1000;
auto constraint = (p * r == Q) + (q * r == P);
auto f = -r + constraint * 1000;
f.simplify_as_binary();
auto solver = qbpp::easy_solver::EasySolver(f);
solver.time_limit(1.0);
auto sol = solver.search();
std::cout << "GCD = " << sol(r) << std::endl;
std::cout << sol(p) << " * " << sol(r) << " = " << P << std::endl;
std::cout << sol(q) << " * " << sol(r) << " = " << Q << std::endl;
}
In this program, p, q, and r are defined as integer variables in the range $[1,1000]$.
The expression constraint is constructed so that it evaluates to zero when both constraints are satisfied.
The objective function -r is combined with the constraint term multiplied by a penalty factor of 1000, and the resulting expression is stored in f.
The EasySolver searches for a solution that minimizes f.
The resulting values of p, q, and r are printed as follows:
GCD = 33
21 * 33 = 858
26 * 33 = 693
This output confirms that the GCD of 858 and 693 is correctly obtained as 33.