Math Problem: Find Three Integers
The following math problem can be solved using QUBO++.
Problem
Find integers $x$, $y$, $z$ that satisfy:
\[\begin{aligned} \frac{1}{x}+\frac{1}{y}+\frac{1}{z} = 1\\ 1 < x < y < z \end{aligned}\]QUBO++ program
Since QUBO++ can handle polynomial expressions, we first rewrite the constraints. Multiplying both sides of the first constraint by $xyz$ yields:
\[xy+yz+zx - xyz = 0\]The strict inequalities $x<y<z$ can be encoded as
\[\begin{aligned} 1 &\leq y-x \\ 1 &\leq z-y \end{aligned}\]The following QUBO++ program formulates these constraints as a HUBO expression and solves it using the Exhaustive Solver:
#include "qbpp.hpp"
#include "qbpp_exhaustive_solver.hpp"
int main() {
auto x = 1 <= qbpp::var_int("x") <= 10;
auto y = 1 <= qbpp::var_int("y") <= 10;
auto z = 1 <= qbpp::var_int("z") <= 10;
auto c1 = x * y + y * z + z * x - x * y * z == 0;
auto c2 = 1 <= y - x <= +qbpp::inf;
auto c3 = 1 <= z - y <= +qbpp::inf;
auto f = c1 + c2 + c3;
f.simplify_as_binary();
auto solver = qbpp::exhaustive_solver::ExhaustiveSolver(f);
auto sols = solver.search_optimal_solutions();
std::set<std::tuple<qbpp::energy_t, qbpp::energy_t, qbpp::energy_t>> seen;
for (const auto& sol : sols) {
const auto key = std::make_tuple(x(sol), y(sol), z(sol));
if (seen.insert(key).second) {
auto [x_val, y_val, z_val] = key;
std::cout << "(x,y,z) = (" << x_val << ", " << y_val << ", " << z_val
<< ")\n";
}
}
}
The three constraints are encoded as c1, c2, and c3, and combined into a single objective f.
The Exhaustive Solver searches for optimal solutions of f and prints the resulting
$(x,y,z)$ tuples.
Because f introduces auxiliary variables during binary simplification, the same
$(x,y,z)$ assignment may appear multiple times in the returned solution set.
Therefore, we use a std::set to remove duplicates before printing.
This program produces the following output:
(x,y,z) = (2, 3, 6)
This indicates that the problem has exactly one solution in the searched range, namely $(x,y,z)=(2,3,6)$.